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 Consider a parabola P that is congruent to y=x^2, opens upward,and has its vertex at (2,4) Now find the equation of a new parabola that results if P is A stretched vertically by a factor of 5 B compressed by a factor of 2New parabola should be congruent (the same shape and size) to y = x2, with the same vertex, except it should open downward so its vertex will be its highest point Record the Find a way to change the equation to make the y = x2 parabola move 3 units to the left and stretch vertically, as in part (c)Your new parabola might look like y = 4x2Graph the parabola, y =x^21 by finding the turning point and using a table to find values for x and y Shifting Parabolas Video Khan Academy Parabola congruent to y=x^2

 Change the quadratic equation from standard form to vertex form y=x^24x5 1 Transpose the value to the left side of the equation 2 Complete the square of the expression on the right side of the equation to get a perfect square trinomialThe parent function of all quadratic equations is y = x2 The vertex form of a quadratic equation is y = a(x h)2 k, where (h,k)Graph the quadratic function from vertex form y = 2(x 1)2 Max or Min? Http Www Midwayisd Org Cms Lib Tx Centricity Domain 164 Preap alg ii 4 7b Pdf Y=x^2-4x-5 in vertex form