√完了しました！ parabola congruent to y=x^2 216216-Parabola congruent to y=x^2
Consider a parabola P that is congruent to y=x^2, opens upward,and has its vertex at (2,4) Now find the equation of a new parabola that results if P is A stretched vertically by a factor of 5 B compressed by a factor of 2New parabola should be congruent (the same shape and size) to y = x2, with the same vertex, except it should open downward so its vertex will be its highest point Record the Find a way to change the equation to make the y = x2 parabola move 3 units to the left and stretch vertically, as in part (c)Your new parabola might look like y = 4x2Graph the parabola, y =x^21 by finding the turning point and using a table to find values for x and y Shifting Parabolas Video Khan Academy Parabola congruent to y=x^2
